00:01
For this question, the it will be equal to 2 plus 10 of cos of t plus 10 degree plus 6 of cos of 3t plus 35 degree.
00:17
So this will be equal to i1t plus i2t plus i3t.
00:27
Now for the case 1, that is i1t.
00:32
This will be equal to 2.
00:34
So here we have the 2a and here we have the ohm, that is 10 ohm and the current that is ir1.
00:46
So this is connected.
00:50
So ir1 is equal to 2a.
00:52
Now for the case 2, this is for the case 1 where i1t is equal to 2.
01:01
Now for the case 2, i2t is equal to 10 of cos of t plus 10 degree and i2 bar is equal to 10 of angle 10 degree.
01:15
Now here w is equal to 1.
01:18
So x of c will be equal to 1 divided by wc which means 1 divided by 2 will be equal to 0 .5 ohm.
01:25
So the circuit diagram will be like this.
01:28
Here we have i2 bar and here we have the 10 ohm resistance and the current that is i bar r2 and here we have minus 10 point, this is minus 0 .5 i0 .5.
01:48
So this is attached with this.
01:52
Now for the ir2, this will be equal to i2, that is i bar of ir2.
01:58
This will be equal to i2 which is multiplied by minus of i0 0 .5 divided by 10 minus i0 0 .5.
02:13
So this will be equal to 10 degree, angle 10 degree plus which is multiplied by, this is multiplied by minus of i0 0 .5 divided by 10 minus i0 0 .5...