Determine the center and radius of the following circle equation: $x^2 + y^2 + 10x - 10y + 46 = 0$ Center: Radius:
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In this case, we have x^2 + (y - 5)^2 + 46 = 0. To get it in standard form, we need to isolate the squared terms on one side and move the constant term to the other side. x^2 + (y - 5)^2 = -46 Now, we can see that the center of the circle is at (h, k) = (0, 5) Show more…
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