Determine the change in pressure on a object submerged in seawater, initially at a depth of 31 meters, descending to a depth of 189 meters . Answer to the nearest kilopascal
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To determine the change in pressure on an object submerged in seawater as it descends from a depth of 31 meters to a depth of 189 meters, we can follow these steps: ** Show more…
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When a submarine dives to a depth of $120 \mathrm{~m}$, to how large a total pressure is its exterior surface subjected? The density of seawater is about $1.03 \mathrm{~g} / \mathrm{cm}^{3}$. $$ \begin{aligned} P &=\text { Atmospheric pressure }+\text { Pressure of water } \\ &=1.01 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}+\rho g h=1.01 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}+\left(1030 \mathrm{~kg} / \mathrm{m}^{3}\right)\left(9.81 \mathrm{~m} / \mathrm{s}^{2}\right)(120 \mathrm{~m}) \\ &=1.01 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}+12.1 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}=13.1 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}=1.31 \mathrm{MPa} \end{aligned} $$
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