00:01
In this question we are asked to find the current in each register for case a, b, c and d in the given circuit.
00:11
Here the value of r1, r2, r3, r4, v and l are given.
00:19
Now first we solve part a.
00:23
Now before solving part a, first we draw this circuit before closing the switch.
00:28
Before closing the switch, the circuit looks like this.
00:35
Here this circuit is disconnected from the supply, that means here current flowing in the each branch is equal to 0.
00:42
And hence we can say here this current is also equal to 0.
00:47
Let us assume that this current is equal to il.
00:51
Now before closing the switch, here current flowing to inductor is il0 minus, means current flowing in the inductor just before the closing the switch is equal to il 0 minus and here this is equals to 0 now we know current through inductor does not change suddenly that means il 0 minus is equal to il 0 is equal to il 0 plus means current through inductor just before closing the switch is equal to current through inductor at the instant of closing the switch is equal to current through inductor just after closing the switch.
01:39
And here because il 0 minus is equal to 0, that means il0 minus is equal to il 0 plus they all becomes equal to 0.
01:51
Now we close the switch.
01:55
And at this moment when we close the switch the current through inductor is equal to 0.
02:01
So just after closing the switch, the current through register r1 is equal to 0.
02:07
That means ir1 is equal to 0.
02:10
Now suppose here this current is equal to i, then this current also become equal to i because here no current is flowing.
02:18
Now by applying kirchof voltage low, we can find the value of current i.
02:23
So now we apply kirchop voltage low.
02:25
So after applying kirtchof voltage low, we obtain v is equal to r2 plus r2 plus r2.
02:32
3 plus r4 i and from this we obtain the value of i is equal to v over r2 plus r3 plus r4 and by putting all these values we obtain i equal to 12 over 100 plus 100 and after simplifying this we obtain the value of i is equal to 0 .03 mp here and here this current i is the current flowing through register r4, r3 and r2.
03:03
That means the current flowing through register r2 r3 and r4 is equal to 0 .03m...