Determine the elongation of the rod in the figure below if it is under a tension of $4.9 \times 10^3$ N. cm 0.20 cm Aluminum Copper 1.3 m 2.6 m
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The force is given as 4.9 x 10^3 N and the area can be calculated using the formula area = (pi * (diameter/2)^2), where the diameter of the rod is given as 0.20 cm. Show more…
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