00:02
In this question, let us see the figure which is given to us.
00:06
So this is our figure.
00:07
Here f1 is equal to the 4050 lb, f2 will be equal to 2220 lb.
00:16
A is equal to 5 .2 feet.
00:19
B is equal to 7 .8 feet.
00:23
C is equal to 3 feet and the value of d is equal to 4 .1 feet.
00:28
So let's take adjoint a.
00:30
At joint a, submission of forces in y direction is equal to 0.
00:34
So we are getting minus fab into y plus f1, it is equal to 0.
00:41
So fab in y direction, vertical direction, it will be equal to the 4050lb and the tan theta will be equal to c by a.
00:53
So it is equal to fab y upon a is fab b into x so that implies f ab x 10 theta is it will be equal to it will be equal to it will be equal to 4 0 5 0 into 5 point 2 upon 3 1 putting and solving we get x 7 0 2 0 lb so the resultant force resultant force f ab will be equal to the under root of fab x square under root of fab x square plus fab y square and when we are putting these values and solving we get this fab it is equal to 8104 .498 lb and the direction will be and it will be in tension it is in tension so in the second joint so so summation of forces in x direction is equal to 0.
01:47
So that implies that employs fabx.
01:51
It is equal to the minus.
01:54
It is equal to the fae.
01:56
So that employs fae...