00:01
So let's start the explanation of the question.
00:08
So there is some equation like this.
00:10
So we know that the use relative, the use relative minus analysis to determine diode current.
00:37
Analysis to determine diode to determine diodes current, diode current.
01:09
So we can say that the vod, which is equal to iv, 1v.
01:19
And the r which is equal to one oom, one kilo oom, and the is, which is equal to 10 minus 15a.
01:41
So the vd, which is equal to 0 .7, and the id, which is equal to vdd, minus vd over r, vd over r.
02:16
So which is equal to 1 minus 0 .7 over thousand so which is equal to 0 .3 amma so we also know that there is some diagram like this so we can see that this is the r and this is vd and this is vod and this point to this point which is i o so we can write this equation the vd the which is equal to v t minus lm into i0 over i s which is equal to 0 .0 .0 into l n into 0 .3 into 10 dash power minus 3 over 10 dash to power minus 15.
04:34
So the vd which is equal to 0 .6607.
04:49
So now we discuss part b...