00:01
According to the question, a solution is formed where nephthylene act as a nephaline, that is, c10, h, 8.
00:11
This molecule act as a solute.
00:13
So we have nephaline as solute and benzene as solvent.
00:18
Solvent is benzene c6, h6.
00:23
And the amount of nephthylene given is equal to the mass of c10h8, that is nephthaline, given is 78 .8 gram and also its molar mass, molar mass of nephaline is equal to 128 .16 gram per mole.
00:43
And the volume of solvent, that is volume of benzene given, is equal to 722 milliliter.
00:50
And also density of benzene given is 0 .877 gram per milliliter.
00:56
And we have to calculate the value of freezing point of a solution given that the freezing point of pure solvent that is tf0 is equal to 5 .50 degrees celsius and the value of kf that is freezing point depression constant is equal to 4 .90 degrees celsius per molar.
01:21
Now, first of all, we will calculate the mass of solvent with the help of formula that density is equal to mass divided by volume.
01:30
We can calculate the mass of solvent...