00:01
In the question we have given for nth orbit en is equals to minus e0 divided with n square.
00:13
Now here n is equals to 1, 2, 3 and so on.
00:18
Now here e0 is the ground state energy.
00:21
It is given as 13 .6 electron volt.
00:34
Now substituting the values e2 is equals to minus of 13 .6 divided with 2 square.
00:41
It is equals to minus of 13 .6 divided with 4 which is equals to minus of 3 .4 electron volt.
00:51
Similarly e3 is equals to minus of 13 .6 divided with 3 square which is equals to minus of 13 .6 divided with 9.
01:00
It is equals to minus of 1 .51.
01:06
Similarly when we calculate e4 this is electron volt.
01:13
E4 is minus 13 .6 divided with 4 square.
01:17
This will comes out to be minus 13 .6 divided with 16 which is equals to 0 .85 electron volt.
01:27
Now the energy of photon emitted is equals to e is equals to minus of 1 .51 plus 3 .4 which is equals to 1 .59 electron volts.
01:52
E is equals to h mu substituting the values 1 .89 multiplied with 1 .6 multiplied with 10 raised to the power minus 14 joules...