00:01
The question that is given over here, it says that we need to find out the internal normal force in this case and also the sheer force and bending moment acting on this beam.
00:17
So if we see the diagram, so if we watch the free body diagram, it is ax and again this is ay.
00:30
This is about negative 1 .5 feet this is nc the force it acts like this and then this is 1 .5 feet b y 3 feet and then it is w and x this is the free body diagram here the triangle load into the point load the w is equal to 1 divided by 2 multiplied by 3 multiplied by 200 so this is equal to 300 lb.
01:19
And also the x value, this can be written as l divided by 3, which is 3 divided by 3 equal to 1 feet.
01:28
So if we take the moment, if we take the moment about a, then 3by will be equal to 300 multiplied by 3, multiplied by 1 .5 plus 300 multiplied by 3.
01:49
3 plus 1 and the b y value and so is 850 lb and also we can say that summation fy will be equal to 0 so y plus b y is equal to 300 multiplied by 3 plus 300 so a y value will be equal to 350 lb and summation fx is equal to y summation f x is equal to zero so in this case a x is also zero so the normal force at see summation f x is zero this is the normal force c so here in this case a x is equal to nc so this is a x is equal to nc is equal to zero so the sheer force at a this can be written as da is equal to ay is equal to 350 lb...