Determine the magnitude of the force on an electron traveling at 8.75 x 10 ^ 17 m / s horizontally eastward in a vertically upward magnetic field of intensity 0.75 T
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Step 1
6 x 10^-19 C - Velocity of the electron (V) = 8.75 x 10^17 m/s - Magnetic field strength (B) = 0.75 T - Angle between velocity and magnetic field (θ) = 90° Show more…
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