00:01
In the question vector bc bar equal to 1 .8 i cap plus 1 .2 j cap minus 0 .6 k cap and it is in meter.
00:31
F bar force f bar equal to 300 minus 2 i cap.
00:48
Plus 4 j cap plus k cap newton now unit vector u cap will be equal to unit vector u cap will be equal to bc bar divided by magnitude of bc bar so bc vector is 1 .8 i cap plus 1 .2 j k cap minus 0 .6 k cap divided by magnitude of bc vector is under root 1 .8 square plus 1 .2 square plus 0 .6 square.
01:49
Now from this we will get unit vector u cap equal to 0 .802.
01:59
Cap plus 0 .5345j cap minus 0 .2672 k cap.
02:16
This is unit vector.
02:19
Now moment vector is, let us consider moment vector along bc is its magnitude will be ucap .u cap dot rbc vector cross f bar vector.
02:45
Now we know that unit vector is 0 .802 icap plus 0 .535j cap minus 0 .2672 k cap.
03:04
This is ucap vector.
03:08
Now, r cross f bar is i cap, j cap, k cap and coefficient of ijk are 1 .8, 1 .2, minus 0 .6...