00:01
So we are given this situation and the system is in equilibrium.
00:04
That means net force in x direction is equal to 0 and net force in y direction is equal to 0 as well.
00:11
Now for the case when the net force in x direction is equal to 0, we can say that, we can say that ax minus fb must be equal to 0.
00:22
That is ax value is equal to magnitude of the fb.
00:26
That is 345 newton.
00:28
So the value of ax is equal to 345 neuter.
00:31
Now also as we know that net force in wide action is equal to zero, that means fa must be balanced out by by plus ay, that is net downward force must be balanced out by net upward force.
00:45
And let's first of all let's calculate the torque about this point a.
00:49
As the system is in equilibrium, that means we can say that net torque about point a must be zero as well.
00:57
So from here the net anti -clockwise torque would be due to b -y only.
01:02
We can say that it is equal to b y times 8 plus 4 that is 12 and we always consider counter clockwise direction as positive and clockwise direction as negative okay so the talk due to b y would be positive and talk due to a f a would be negative and it would be minus f a times 4 and this must be because the torque about this force would be 0 okay and a x and a y about point over would be 0 as well.
01:33
So from here we can say that the value of by is equal to f .a...