Question

Determine the magnitude of the resultant force and its direction $\theta$, measured counterclockwise from the positive $x$ axis. $F_2 = 600$ N $F_1 = 800$ N $45^\circ$ $60^\circ$ $13$ $5$ $12$ $F_3 = 650$ N $y$ $x$

Name: determine the magnitude of the resultant force and its direction theta measured counterclockwise from the positive x axis f2 600 n f1 800 n 45circ 60circ 13 5 12 f3 650 n y x 16936
Uploaded: 2022-11-09T09:27:18-08:00
Duration: 2 min 42 s
Channel: Sri K
Description: determine the magnitude of the resultant force and its direction theta measured counterclockwise from the positive x axis f2 600 n f1 800 n 45circ 60circ 13 5 12 f3 650 n y x 16936

          Determine the magnitude of the resultant force and its direction $\theta$, measured counterclockwise from the positive $x$ axis.
$F_2 = 600$ N
$F_1 = 800$ N
$45^\circ$
$60^\circ$
$13$
$5$
$12$
$F_3 = 650$ N
$y$
$x$

determine the magnitude of the resultant force and its direction theta measured counterclockwise from the positive x axis f2 600 n f1 800 n 45circ 60circ 13 5 12 f3 650 n y x 16936

Added by Mary H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

11/09/2022

Step 1

For $F_1 = 800$ N: The angle $F_1$ makes with the positive x-axis is $60^\circ$. $F_{1x} = F_1 \cos(60^\circ) = 800 \cos(60^\circ) = 800 \times 0.5 = 400$ N $F_{1y} = F_1 \sin(60^\circ) = 800 \sin(60^\circ) = 800 \times \frac{\sqrt{3}}{2} \approx 800 \times 0.866 Show more…

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Determine the magnitude of the resultant force and its direction $\theta$, measured counterclockwise from the positive $x$ axis. $F_2 = 600$ N $F_1 = 800$ N $45^\circ$ $60^\circ$ $13$ $5$ $12$ $F_3 = 650$ N $y$ $x$