00:01
In this question, a jib brain is shown and here we have to find the tension in the supporting cable and also the magnitude of the force on the pin at a, that is here.
00:12
And it is also given that the mass of the jib crane is 95 kilogram per meter, that is 95 kilogram per meter and which means that the total length of the frame is 5 meter.
00:27
It means the mass of is going to be 95 times 5.
00:33
That is nothing but 475 kilograms.
00:40
And now we have to find two parameters here, as i mentioned now, the tension that is acting on the supporting cable and the magnitude of the force on the pin at 8.
00:51
Let's do it.
00:53
Before that, we have to consider the tension that is acting on the cable.
00:57
So we let's just draw it.
01:00
The angle is given that is 25 degree and here it is the sign component that is t sign 25 degree and here is our course component which is going to be t course 25 degree and here is our let's say at this point there is a force due to this cable that is acting and it is going to be ax and as the supporter is on the upward direction, the support is from the upward direction, and then the ay component is going to be like this only.
01:43
So we are already sorted out the ax and ay force components.
01:47
And now let's find the moment about a.
01:51
That is the moment about a.
01:52
Moment is nothing but moment is equal to force times the purpose.
02:02
Perpendicular distance.
02:08
So here the crane is balanced actually...