Determine the margin of error for a 90% confidence interval to estimate the population mean when s = 42 for the sample sizes below. a) n = 12 b) n = 27 c) n = 49 a) The margin of error for a 90% confidence interval when n = 12 is . (Round to two decimal places as needed.) b) The margin of error for a 90% confidence interval when n = 27 is . (Round to two decimal places as needed.) c) The margin of error for a 90% confidence interval when n = 49 is . (Round to two decimal places as needed.)
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Given: - Confidence level (1 - α) = 0.90 - Sample standard deviation (s) = 42 - Sample size (n) = 12 Using the formula for margin of error: Margin of Error = z * (s / √n) For a 90% confidence interval, the z-value can be found using a standard normal Show more…
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