00:01
Given this equation, we have aluminum hydroxide reacting with hcl, forming aluminum chloride and water.
00:07
If you start with 0 .750 grams of aluminum hydroxide, how many grams of hydrochloric acid are going to be needed? we don't have a molarity for hydrochloric acid, so i'm assuming this is just a mass or a generic mass of hydrochloric acid.
00:24
I'm also not going to assume any sort of solubility here, i'm just going to be treating this as a limiting reactive problem.
00:30
So let's start with the 0 .750 grams of aluminum hydroxide.
00:37
To shorten this, i'm just going to say alh.
00:40
So that's aluminum hydroxide.
00:44
From here, we're going to convert this to moles.
00:47
So one mole on the top is going to equal the molecular weight, or 78 .004 grams.
00:54
So now we're in moles of alh...