00:01
Now in this problem we are given with this pulley block system and the force applied to one side of this rope is given to be 500 newton and the acceleration due to gravity its value is 9 .8 meter per second squared.
00:20
Now we need to find the mass of this block a up to four decimal places.
00:29
Okay so to find the mass of this block we need to find the force acting at in this rope.
00:37
Let this force be t.
00:40
T1, ta i can write.
00:43
Okay so first we know that here the force is 500 newton.
00:49
Now if you consider this pulley, let this pulley be one, pulley number two, pulley number three.
00:54
So if you consider pulley number one, here the force is f correct and here the force acting would also be f because the same rope is there and there is no friction and here this would be 2f.
01:12
So that this pulley is in equilibrium.
01:15
Now if you consider the second pulley, this was the diagram for the first pulley.
01:20
If you consider the second pulley, now here the force would be f here like this and here the force would be f correct.
01:32
Now in this rope, in this rope the force should be 2f so that the net forces in the y direction are balanced.
01:40
So here in this rope the tension should be 2f correct...