00:01
In this question, we will be solving for the molecular formula of the given compound here.
00:06
So we assume 100 grams.
00:11
Therefore, we will have 57 .14 grams carbon, 6 .16 grams of hydrogen, 9 .52 grams, nitrogen, and 27 .18 grams of oxygen.
00:24
Next, we need to solve for the moles of each element.
00:28
Where moles of each element is equals to mass divided by molar mass.
00:33
So, mole of carbon is from 57 .14 grams divided by 12 .01 grams per mole is equals to 4 .78 mole.
00:46
Next, mole of hydrogen equals 6 .16 grams divided by 1 .01 grams per mole.
01:00
Is equals to 6 .099 next mole of nitrogen equals 9 .52 grams divided by 14 .01 grams per mole.
01:14
This is equals to 0 .6795 mole...