00:01
So, here we have to determine the moment of the force.
00:03
So, let us say we are given this figure from here it is making an angle of 45 degree with the horizontal force is given that is equals to 5 kilo newton.
00:14
So, force is 5 kilo newton this distance is given from here that is d which from here is making an angle of 75 degree and this is making an angle of 30 degree with the horizontal this is its fixed point let us say this is the point o.
00:29
So, this is the system which we are considering here if we simplify let us say this is the point o this is basically its fbd.
00:38
So, this from here is given as 5 multiplied by the cos of 45 degree that is equals to fx and f multiplied by the sin of 45 degree is equals to fy where we are given the value of d dx that is equals to 3 cos of 30 degrees.
00:55
So, the value of gamma is equals to r cross f from here let we are considering that o is the origin if o is the origin from here.
01:04
So, the value of r bar become equals to 3 cos of 30 i cap plus 3 sin of 30 j cap...