00:01
I in this question we have a rod of length l so the rod is ab now we have so using parallel access theorem we have the moment of inertia a is equal to i into g plus m l by 2 whole square so this is at the center of mass and this is at due to the rod so ia becomes equal to m into l square by 12 plus m l square by 4 which is equal to m l square by 3.
00:39
Now the rod is pushed down by creating an angle theta.
00:48
So here it is hinge to form an angle theta.
00:54
So this is theta angle.
00:57
So now here it is theta.
01:00
So now the energy of the system is the.
01:06
Energy of system will be due to rod plus spring.
01:16
So energy becomes equal to half k into l theta square.
01:22
So this is opposite side.
01:25
So this is l into theta.
01:26
So l theta square plus half into ia into d theta by dt whole square which is equal to constant.
01:37
So this is the total energy of the system.
01:40
This is due to rod and this is due to spring vice versa this is due to spring and this is due to rod...