Determine the number of grams of HO produced from 4.94 g of Al(OH)3 Al(OH)3 (s) + 3 HCI(aq) → AlCl3(aq) + 3H20(I)
Added by Valerie W.
Step 1
- Aluminum (Al) = 26.98 g/mol - Oxygen (O) = 16.00 g/mol - Hydrogen (H) = 1.01 g/mol - Molar mass of Al(OH)3 = 26.98 + (3 × 16.00) + (3 × 1.01) - Molar mass of Al(OH)3 = 26.98 + 48.00 + 3.03 = 78.01 g/mol Show more…
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