Determine the number of grams of sucrose, C12H22O11, needed to make 500.0 mL of a 0.125 M sucrose solution. Molar mass sucrose C12H22O11 = 342.30 g/mol
Added by Eva K.
Step 1
Given: Molarity (M) = 0.125 mol/L Volume = 500.0 mL = 0.5 L Number of moles = Molarity x Volume Number of moles = 0.125 mol/L x 0.5 L Number of moles = 0.0625 moles Show more…
Show all steps
Your feedback will help us improve your experience
Vishal Sharma and 95 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Calculate the % m/V of 500.0 mL of solution containing 100.0 grams sucrose, (C12H22O11). and Calculate the molarity of sucrose solution in question1.
Adi S.
How many grams of sucrose, C12H22O11 are required to prepare 2.50 L of solution whose concentration is 0.650 M? Show your solution.
Sima S.
What mass of sucrose (C12H22O11) would you combine with 5.00 * 102 g of water to make a solution with an osmotic pressure of 8.55 atm at 298 K? (Assume a density of 1.0 g>mL for the solution.)
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD