Determine the [OH?], pH, and pOH of a solution with a [H?] of 2.1 x 10?¹² M at 25 °C. [OH?] = pH = pOH = M
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1 x 10^(-12) M, we can use the equation for the ion product of water to find [OH^(-)]: [H^+][OH^-] = 1.0 x 10^(-14) at 25°C 2.1 x 10^(-12) [OH^-] = 1.0 x 10^(-14) [OH^-] = (1.0 x 10^(-14)) / (2.1 x 10^(-12)) [OH^-] = 4.76 x 10^(-3) M Show more…
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