Question

Determine the $[OH^-]$, pH, and pOH of a solution with $[H^+]$ of $2.2 \times 10^{-12}$ M at 25 $^\circ$C. A. $[OH^-](M)$ $2.2 \times 10^{-12}$ $pH$ $11.66$ $pOH$ $2.34$ B. $[OH^-](M)$ $4.5 \times 10^{-3}$ $pH$ $11.66$ $pOH$ $2.34$ C. $[OH^-](M)$ $2.2 \times 10^{-12}$ $pH$ $2.34$ $pOH$ $11.66$ D. $[OH^-](M)$

          Determine the $[OH^-]$, pH, and pOH of a solution with $[H^+]$ of $2.2 \times 10^{-12}$ M at 25 $^\circ$C.
A. $[OH^-](M)$ 
$2.2 \times 10^{-12}$
$pH$
$11.66$
$pOH$
$2.34$
B. $[OH^-](M)$
$4.5 \times 10^{-3}$
$pH$
$11.66$
$pOH$
$2.34$
C. $[OH^-](M)$
$2.2 \times 10^{-12}$
$pH$
$2.34$
$pOH$
$11.66$
D. $[OH^-](M)$

Determine the [OH^-], pH, and pOH of a solution with [H^+] of 2.2 × 10^-12 M at 25 ^∘C.
A. [OH^-](M)
2.2 × 10^-12
pH
11.66
pOH
2.34
B. [OH^-](M)
4.5 × 10^-3
pH
11.66
pOH
2.34
C. [OH^-](M)
2.2 × 10^-12
pH
2.34
pOH
11.66
D. [OH^-](M)

Added by Jesse H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Oluwapelumi Kolawole

07/02/2023

Step 1

0 x 10^-14. Given [H*] = 2.2 x 10^-12 M, we can solve for [OH]: (2.2 x 10^-12)([OH]) = 1.0 x 10^-14 [OH] = (1.0 x 10^-14) / (2.2 x 10^-12) [OH] = 4.55 x 10^-3 M Show more…

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Determine the [OH].pH,and pOH of a solution with [H*] of 2.210-12Mat 25C DA W)[HO] He pOH 2.2x10-12 11.66 2.34 B. [OHM pH pOH 4.5x10-3 11.66 2.34 [OH]M 2.21012 pH pOH 2.34 11.66 OD. [OH]M) pH pOH