00:01
Hi, so to solve for this, we need to write our i's table for this.
00:05
If we have this acid, ha, this will dissociate to hydrogen ion and deconjugate phase.
00:12
Now our i's table, initial change equilibrium concentration.
00:16
Initial concentration is 0 .48 molar.
00:19
The products are zero initially.
00:21
This will lose some amount and this will gain and this will gain.
00:24
At equilibrium, we have 0 .48 minus x, x and x.
00:29
We're calculating the ph, so that means we have to find the value of the hydrogen ion concentration at equilibrium, which is equivalent to x.
00:37
So how do we solve for the value of x? we will use the given ka.
00:42
Acid dissociation constant is equivalent to the concentration of the products.
00:46
So our products are hydrogen ion and deconjugate phase a minus over the concentration at equilibrium of the solution or the acid.
00:57
Plug in the information that we have, ka is 3 .3 times 10 to the negative 6 and then h plus at equilibrium is equivalent to x and also a minus, it's equivalent to x...