Determine the ph of a strong base a list the 6 strong bases...

Determine the pH of a strong base: a. List the 6 strong bases. b. Calculate the pH of 0.05M solution of NaOH c. Calculate the pH of 0.05M solution of Ca(OH)_(2). Comment on the difference between your answers to b and c ! 3. Determine the pH of a strong base: a. List the 6 strong bases b. Calculate the pH of 0.05M solution of NaOH c. Calculate the pH of 0.05M solution of Ca(OH)2. Comment on the difference between your answers to b and c!

Transcript

00:01 Hey welcome to the video, we know that ph is equal to minus log of h plus and over here hcl is a strong acid so it would get completely dissociated into h plus plus cl minus and therefore the concentration of h plus would be equal to the concentration of hcl.

00:16 From this, we would have the ph of the hcl to be equal to minus log of 0 .001 and this would be equal to 3 and next we have a weak acid which is ch3cooh which is a weak acid and it won't get completely dissociated so therefore we would have a ka to be equal to the concentration of ch3coo minus into h plus divided by the concentration of the acid and over here if the ka value is given we can calculate the h plus value which is also equal to the anion value and over here if the both the values that is concentration be termed x then x square would be equal to the concentration of the acid into the concentration sorry the concentration of the acid which is 0 .001 into the constant which is 1 .8 into 10 to the power minus 5 and this would be equal to 1 .8 into 10 to the power minus 8 and from this x which is equal to the concentration of h plus would be equal to 1 .341 into 10 to the power minus 4 and from this we can get the ph to be equal to minus log of 1 .341 into 10 to the power minus 4 and it would be equal to 4 log 10 minus log of 1 .341 and this would be equal to 4 minus 0 .1274 and which is equal to that is the ph is equal to 3 .8726 and next we have base where we can calculate the poh where we know that poh is equal to minus log of oh minus and from the poh we can calculate the ph from the relation that exists between ph and poh where ph plus poh is equal to 14 and therefore from this naoh is a strong base and it would get completely dissociated into na plus plus oh minus therefore the concentration of oh minus is equal to the concentration of naoh and that would be equal to that is the poh would be equal to minus log of 0 .001 and it would be equal to 3 from this the ph would be equal to 14 minus 3 and hence the ph of the solution is equal to 9 and we have ammonia which is a weak base which is nh3 this on reaction with water would produce nh4 plus plus oh minus and this would be in equilibrium...

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