Determine the phase angles by which v1(t) leads i1(t) and v1(t) leads i2(t), where v1(t) = 4 sin (377t + 25°) V i1(t) = 0.05 cos (377t - 20°) A i2(t) = -0.1 sin (377t + 45°) A
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v1(t) = 4sin(377t + 259) i(t) = 0.05cos(377t - 209) i2(t) = -0.1sin(377t + 459) The phase angles are: v1(t): 259° i(t): -209° (converted to sine: 90° - (-209°) = 299°) Show more…
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