00:01
Hello, in this question here we need to determine the product of each carboethylic acid reaction.
00:07
So here in this first case, we have ch3, ch2, c double bond o, oh it is there.
00:16
So when it is reacted with n -a -o -h, this is n -a -p positive and o -h -negative it is there.
00:23
So this o -h -negative, it will try to attack at this hydrogen.
00:30
So therefore it will abstract acetic proton.
00:33
So this is the acidic proton here this is partial negative and partial positive it is there.
00:38
And hence there will be the delocalization of electron will take place.
00:43
So as it gets negative charge so therefore this na positive will try to attract at this partial per negative charge of oxygen.
00:53
So here we will have this ch3, ch3, ch2, c double bond o, o, and n -a -o -negative and n -a -positive plus h -2o will remove.
01:13
So this is the sodium salt of propanoic acid.
01:23
So this is the product is formed.
01:27
So always carboxylic acid form the sodium salt of the carbo -oxylate with n -a -o -h.
01:32
Here in the next reaction we have reactant it is c.
01:37
Ch3, ch2, ch2, c double bond o, oh, this is a carboxylic acid, when it reacts with h2 so4.
01:47
That means acid catalyzed...