00:01
That's of the given quotient.
00:01
In this quotient we have to calculate the momentum at point o due to the force f1 and f2.
00:09
Now the force value that is f1 is given by the force f1 is equals to 480 newton and force f2 is equals to 620 newton.
00:27
The total distance here it is 0 .125 and 0 .8 that is 0 .14 sorry 425 centimeter and distance is 0 .25.
00:41
Here due to the force one there are two components that is one is along the x -axis and another is along the y -axis.
00:50
Here due to f2 there is one force that is f2 cos 60 degree and here is another force in the y -axis that is f2 sin 60 degree.
01:05
The force along the x -axis moves the lever in the clockwise direction means to say the clock the lever gets on.
01:15
Similarly the due to the y -axis the lever moves in the anticlockwise direction and it's got off.
01:24
On calculating first of all we calculate the value of f1 in the x direction force in the x direction where we say that 480 into 4 by 5.
01:35
On solving this we get the value of 384 newton.
01:39
Similarly force one in the y direction which is equals to 480 into 3 upon 5.
01:52
On solving this we get the value of f1 by 280.
01:55
We get value 480 that is 3 by 5.
01:59
On solving this we get values 288, 288 newton.
02:04
Similarly for the force two that is f2 in the x direction is given by f2 cos 60 degree...