Determine the resultant of the concurrent forces in non...

Determine the resultant of the concurrent forces in non-coplanar system having the following magnitudes that passes through the origin towards the indicated points. Also identify its pointing and its angle of inclination. P=450 kN (+4,+2,+4) T=360 kN (+5,-2,-4) F=320 kN (-3,+5,-3)

Transcript

00:01 Value of p which is equal to the 450 kilo newton or we can plus 4 plus 2 and plus 4 the points here is given and the value of t is given which is 360 kilo which is at point plus 5 minus 2 minus 4 and similarly we are given the value of f which is 320 kilo newton at the point minus 3 plus 5 and minus 3 so now we have to find out the distance, which is equals to the under root of x square plus y square plus c squared.

00:38 So component of forces is f of x divides by the x plus f of which is equals to the f of y divides by the i, which is equal to the f of z divides by the z, which is further is equal to the f divides by the t.

00:54 So from here we can write it test that f of x is equals to the x, f, divides, by the d and f of y is equal to the y f divides by the d or we can write it as that f of c is equal to the z f divides by the d so from here the component of resultant r x is equals to the summation of f of x r of x which is further equal to the summation of f of y r of y which is further equal to the summation of f of z r of c which is further equal so here we can write it is that the r is equals to the whole and the root of the r x square plus r y square plus r z square so from here we can find out we are having the value of force which is 450 360 and 320 so for the value of x at 4 5 minus 3 the value of y at 2 minus 2 minus 2 and 5 and the value of z at 4 minus 4 and minus 3 and further from here the value of d is 6 .7 1 6 .5 8 and from this d we can find out the value of fx which comes out to be 300 to 68 .268 .26 minus 145 .9 or we can write it is r of x is equal to the 422 .36 similarly f of y is 150 minus 107 .30 to 243 .16 so from here the r of y is equal to the 258 .86 and similarly the value for f of z is 300 minus 214 .61 minus 145 .9.

03:02 So from here we can write it as that r of c is equal to minus 60 .51.

03:07 So from here we can write the test direction of course theta x equals to rx divides by the r which comes out to be 0 .822 theta x...

Question

Determine the resultant of the concurrent forces in non-coplanar system having the following magnitudes that passes through the origin towards the indicated points. Also identify its pointing and its angle of inclination. P=450 kN (+4,+2,+4) T=360 kN (+5,-2,-4) F=320 kN (-3,+5,-3)

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