Question

Determine the sample size needed to obtain an estimate of mu if the margin of error E=0.10,sigma =0.75, and the confidence level is 998 (use z_(0005)=2.57 ). Use Table IV in Appendix C to compute the probabilities. Recall the following definitions from section 8.8 of the text. Given the confidence level and the standard deviation of the population, the sample size that will produce a predetermined margin of error E of the confidence interval estimate of mu is n=(z^(2)sigma ^(2))/(E^(2)) where the value of z is obtained from the standard normal distribution (Table IV in Appendix C or by calculator) and the quantity zsigma _(x) is called the Margin of Error and is denoted by E. Furthermore, sigma _(ar{x} )=(sigma )/(sqrt(n)) is the standard deviation of ar{x} . Alternatively, To obtain z from a graphing calculator, we use the formula z= invNorm (1-(alpha )/(2),mu ,sigma ) where mu is the mean and sigma is the standard deviation of the normal distribution. For the standard normal distribution mu =0 and sigma =1. Recall that in general z= invNorm("area to left of z,mu,sigma. Chapter 08, Section 8.2, Intelligent Tutoring Problem 017 It is given that E=0.10 and sigma =0.75. (a) Find a for 99% confidence level. (b) Find 1-(a)/(2) 1-(a)/(2)=◻ (c) Find z_((a)/(2)) for 399% confidence level. z_((0)/(2)) use z0.005=2.57 Use Table IV in AppendixC to compute the probabilities Recall the following definitions from section 8 of the text Given the confidence level and the standard deviation of the population,the sample size that will produce a predetermined margin of errorEof theconfidence intervalestimate ofisn= 2202 E2 where thevalue of z is obtained from the standard normal distribution(Table IVin Appendix Cor by calculator)and the quantity zo is called the Margin of Error and is denoted by E.Furthermore, V is the standard deviation of x Alternatively.To obtain z from a graphing calculator.we use the formulaz=invNorm(1-a/2.g where is the mean and g is the standard deviation of the normal distribution.For the standard normal distribution=O and a=1 Recall that in generalz=invNormarea to left of z Chapter08.Section 8.2,Intelligent Tutoring Problem017 It is given thatE=0.10anda=0.75 (aFind a for99%confidence level (bFind1-a/2 1-a/2= (c)Find za/for a99%confidence level Za/2

          Determine the sample size needed to obtain an estimate of mu  if the margin of error E=0.10,sigma =0.75, and the confidence level is 998 (use z_(0005)=2.57 ).
Use Table IV in Appendix C to compute the probabilities.
Recall the following definitions from section 8.8 of the text.
Given the confidence level and the standard deviation of the population, the sample size that will produce a predetermined margin of error E of the confidence interval estimate of mu  is n=(z^(2)sigma ^(2))/(E^(2))
where the value of z is obtained from the standard normal distribution (Table IV in Appendix C or by calculator) and the quantity zsigma _(x) is called the Margin of Error and is denoted by E. Furthermore, sigma _(ar{x} )=(sigma )/(sqrt(n)) is the standard deviation of ar{x} .
Alternatively, To obtain z from a graphing calculator, we use the formula z= invNorm (1-(alpha )/(2),mu ,sigma )
where mu  is the mean and sigma  is the standard deviation of the normal distribution. For the standard normal distribution mu =0 and sigma =1. Recall that in general z= invNorm("area to left of z,mu,sigma.
Chapter 08, Section 8.2, Intelligent Tutoring Problem 017
It is given that E=0.10 and sigma =0.75.
(a) Find a for 99% confidence level.
(b) Find 1-(a)/(2)
1-(a)/(2)=◻
(c) Find z_((a)/(2)) for 399% confidence level.
z_((0)/(2))
use z0.005=2.57
Use Table IV in AppendixC to compute the probabilities
Recall the following definitions from section 8 of the text Given the confidence level and the standard deviation of the population,the sample size that will produce a predetermined margin of errorEof theconfidence intervalestimate ofisn= 2202 E2 where thevalue of z is obtained from the standard normal distribution(Table IVin Appendix Cor by calculator)and the quantity zo is called the Margin of Error and is denoted by E.Furthermore, V is the standard deviation of x
Alternatively.To obtain z from a graphing calculator.we use the formulaz=invNorm(1-a/2.g where is the mean and g is the standard deviation of the normal distribution.For the standard normal distribution=O and a=1 Recall that in generalz=invNormarea to left of z
Chapter08.Section 8.2,Intelligent Tutoring Problem017
It is given thatE=0.10anda=0.75
(aFind a for99%confidence level
(bFind1-a/2
1-a/2=
(c)Find za/for a99%confidence level
Za/2

determine the sample size needed to obtain an estimate of mu if the margin of error e010sigma 075 and the confidence level is 998 use z0005257 use table iv in appendix c to compute the prob 58414

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