5 \times 10^3 \text{ N/m} 1.2 m m = 20 kg 0.4 m FIGURE P 2.18 Spring is stretched 20 mm when bar is vertical
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The formula for the force exerted by a spring is given by Hooke's Law: F = k * x where F is the force, k is the spring constant, and x is the displacement from the equilibrium position. In this case, the displacement x is 20 mm, which is equal to 0.02 m. The Show more…
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