00:01
Hello, in this question from the circuit diagram, the 10 -arm resistor and 5 -arm resistor are connected in parallel.
00:06
Hence their equivalent resistance can be expressed as 1 divided by r -4 -5 equals 1 divided by r4 plus 1 divided by r5.
00:18
Here r -4 -5 is the equivalent resistance of the combination of the parallel resistors.
00:23
So we can write 1 divided by r -4 -5 equals 1 -divided by 4 -5.
00:30
10 oom plus 1 divided by 5 om.
00:35
So we get r45 as equal to 3 .33 om.
00:42
Now this combination of resistors is in serious with the resistor r2.
00:47
The equivalent resistance of the serious resistors can be given by r2 -245 equals r2 plus r4 -5.
00:59
Let's substitute the values.
01:01
So it equals 4 om plus 3 .33 om equals 7 .33 om.
01:09
Now the combination of r4, r5 and r2 is in parallel to r1.
01:15
So the equivalent resistance of the resistors can be expressed as 1 divided by r1245 equals 1 divided by r1 plus 1 divided by r2 4 here r1 245 represents the equivalent resistance of the 4 resistors.
01:40
Let's substitute the values...