Question

Determine the theoretical yield of H2S (in moles) if 32 mol Al2S3 and 32 mol H2O are reacted according to the following balanced reaction. A possibly useful molar mass is Al2S3 = 150.17 g/mol. Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H2S(g)

Name: determine the theoretical yield of h2s in moles if 32 mol al2s3 and 32 mol h2o are reacted according to the following balanced reaction a possibly useful molar mass is al2s3 15017 gmol al2s3 06954
Uploaded: 2023-06-16T21:44:48-08:00
Duration: 1 min 29 s
Channel: Chareen Guzman
Description: determine the theoretical yield of h2s in moles if 32 mol al2s3 and 32 mol h2o are reacted according to the following balanced reaction a possibly useful molar mass is al2s3 15017 gmol al2s3 06954

          Determine the theoretical yield of H2S (in moles) if 32 mol Al2S3 and 32 mol H2O are reacted according to the following balanced reaction. A possibly useful molar mass is Al2S3 = 150.17 g/mol.
Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H2S(g)

Added by Alexandra M.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Chareen Guzman

06/16/2023

Step 1

The balanced equation is: \[ \text{Al}_2\text{S}_3(s) + 6 \text{H}_2\text{O}(l) \rightarrow 2 \text{Al(OH)}_3(s) + 3 \text{H}_2\text{S}(g) \] Show more…

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Determine the theoretical yield of H2S (in moles) if 32 mol Al2S3 and 32 mol H2O are reacted according to the following balanced reaction. A possibly useful molar mass is Al2S3 = 150.17 g/mol. Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H2S(g)