Question

Determine the value for c so that $\lim_{x \to 4} f(x)$ exists. f(x) = \begin{cases} x^2 - 8, & \text{for } x < 4\\ -x^2 + c, & \text{for } x > 4 \end{cases} The value of c is

          Determine the value for c so that $\lim_{x \to 4} f(x)$ exists.

f(x) = \begin{cases} x^2 - 8, & \text{for } x < 4\\ -x^2 + c, & \text{for } x > 4 \end{cases}

The value of c is

Determine the value for c so that limx → 4 f(x) exists.

f(x) = x^2 - 8, for x < 4
-x^2 + c, for x > 4

The value of c is

Added by Michelle B.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Madhur L

06/02/2022

Step 1

Step 1: To find the value of c so that \lim_(x->4)f(x) exists, we need to ensure that the left-hand limit and the right-hand limit as x approaches 4 are equal. Show more…

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Determine the value for c so that lim_(x->4)f(x) exists. f(x)={(x^(2)-8, for x<4),(-x^(2)+c, for x>4):} The value of c is Determine the value for c so that lim f(x) exists x-4 x2 - 8, for x<4 x2 +c, for x>4 f(x) The value of c is