00:01
All right guys, we are given the following data for water that is t1 is equal to 150 degree centigrates that is equal to 423 .15 kelvin then we've got p is equal to 400 kilo pascal and then we've got t2 is equal to 1200 degrees centigrade that is equal to 1473 .15 kelvin.
00:36
So guys, let's start with part a of this question.
00:40
That is, from table b1 .3 corresponding to pressure 400 kilopascal and temperature 150 degrees centigrade, we can obtain initial specific internal energy that is u1 is equal to 2564 .48 kilojoules per kg now from table b1 .3 corresponding to p pressure 400 and temperature t1 is equal to 1 ,200 degrees centigrade we can obtain the final internal energy that is u2 is equal to 446 .99 kilojoules per kg so change in entire energy is given as delta u is equal to u2 minus u1 is 4466 .99 minus 2564 2564 .48 is equal to 1902 .5 .5 kilojoules per kg.
02:08
So guys, we've got delta u is equal to 1902 .5 kilojoules per kg.
02:16
So now we move on to part b of this question.
02:20
So from table a8 corresponding to temperature 400 kelvin we can obtain specific internal energy as u is equal to 557 .17 .79 kilojoules per kg from table a 8 corresponding to temperature t is equal to 450 kelvin we can obtain specific internal energy as u is equal to 630 .40 kilojoules per kg so using interpolation we can find initial specific internal energy as u1 is equal to 557.
03:07
Point seven nine plus 423 .15 minus 400 divided by 450 minus 400 multiplied by 630 .40 minus 557 .9 and the answer to u1 is 59 .91 .4 kilojoules per kg.
03:38
So from table a8 corresponding to temperature 1400 kelvin, we can obtain specific internal energy that is u is equal to 2138 .8 .84 kilojoules per kg.
03:55
So from table a8 corresponding to temperature 1500 kelvin, we can obtain the specific internal energy as u is equal to 2531 .28 kilojoules per kg.
04:15
So using interpolation we can find specific internal energy that is u1 is equal to 2318 .89 plus 1473 .15 minus 1400 divided by 1500 minus 1400 multiplied by 2531 .28 minus 231 .8 .89, and that is equal to 2474 .74 .3joules per and the change in internal energy delta u is equal to u2 minus u1 is equal to 2474 .4 .4 .4 .4 .4 .4...