Determine whether the system is i) memoryless, ii) causal, iii) linear, and iv) time-invariant. i. $y[n] = 2x[n]u[n]$ ii. $y(t) = x(t/2)$ iii. $y[n] = x[n] - x[n-1]$
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**System i: $y[n] = 2x[n]u[n]$** **Memoryless:** A system is memoryless if its output at any time depends only on the input at that same time. In $y[n] = 2x[n]u[n]$, the output $y[n]$ at time $n$ depends only on the input $x[n]$ at time $n$ and the unit step Show more…
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