00:01
Homework which will be equal to our free energy that could our temperatures will be standard 25 degrees c and one atmosphere and we'll be using 4 .84 moles of o2 and that's going to be aluminum plus o2 and my product will be aluminum oxide and let's go ahead and put a two here a four here here and a3 here.
00:43
Now let me go find a table of thermodynamic.
00:48
Huh, did i close it? i usually leave one of these open.
00:55
Thermochemical data table, university of wisconsin -madison, and let's get to aluminum.
01:06
Aluminum.
01:07
So aluminum will be, of course, zero.
01:09
This will be zero.
01:12
8l2o3 is negative 1582 .3 kilojoules per mole.
01:21
So my delta g, my reaction, will be equal to two moles, that's this value, times negative 1582 .3 kilojoules per mole, which will equal, let me grab a calculator.
01:49
2 times negative 1582 .3 is negative 3164 .2 kilojoules...