4) Find a power series expansion about $x = 0$ for the solution to the given IVP. $y'' + (x - 2)y' - y = 0$, $y(0) = -1$; $y'(0) = 0$.
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The given differential equation is y" + (x - 2)y - y = 0. To rewrite it in standard form, we rearrange the terms to get y" - y + (x - 2)y = 0. Show more…
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