A dioxin-contaminated water source contains 0.089 % dioxin by mass. How much dioxin is present in 5.0 L of this water? (Assume that the density of the solution is 1.02 g/mL.) Express your answer in grams using two significant figures.
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Given that the water contains 0.089% dioxin by mass, we can calculate the mass of dioxin in 5.0 L of water as follows: 0.089% = 0.089 g/100 g of water Mass of dioxin in 5.0 L of water = 0.089 g/100 g x 5.0 L x 1000 mL/L x 1.02 g/mL = 0.04563 g Show more…
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