00:01
In this problem, we're given the function, h of x is equal to the absolute value of 1 minus x, and we're first being asked to fill in the table.
00:08
So we first need to find the value of h of x when x is negative 2.
00:12
So we need to find h of negative 2, which means we need to substitute negative 2 in for x.
00:18
So we'll have the absolute value of 1 minus negative 2.
00:23
Well, 1 minus negative 2 is positive 3, so we'll have the absolute value of 3, which is just equal to 3.
00:30
So when x is negative 2, h of x is 3.
00:33
Now we'll do the same thing for negative 1.
00:35
We're going to substitute negative 1 and for x.
00:38
So we'll have the absolute value of 1 minus negative 1.
00:41
Well, 1 minus negative 1 is positive 2, and the absolute value of 2 is 2.
00:47
So when x is negative 1, h of x is 2.
00:51
Well, we can do the same thing for 0.
00:53
We're going to substitute 0 and for x.
00:55
So we're going to have the absolute value of 1 minus 0.
00:58
Well, 1 minus 0 is just 1.
01:00
So we'll have the absolute value of 1, which is equal to 1.
01:04
So when x is 0, h of x is 1.
01:07
Now, we'll do the same thing for when x is 1.
01:10
We have h of 1.
01:11
So we're going to substitute 1 for x.
01:13
So we have an absolute value of 1 minus 1.
01:16
Well, 1 is 0.
01:18
So we have the absolute value of 0, which is equal to 0.
01:21
So that means when x is 1, h of x is 0.
01:25
Now we need to find h of 2.
01:27
So we're going to substitute 2 in for x...