Divide. Simplify if possible. $$ \frac{(x+3)^2}{x-3} \div \frac{x^2-9}{3x-9} $$ $$ \frac{(x+3)^2}{x-3} \div \frac{x^2-9}{3x-9} = $$ (Simplify your answer.)
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$$ \frac{(x+3)^2}{x-3} \times \frac{3x-9}{x^2-9} $$ Show more…
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