Question

Divide using long division. State the quotient, q(x), and the remainder, r(x). $(15x^2 + 4x - 1) \div (3x - 1)$ $(15x^2 + 4x - 1) \div (3x - 1) = \frac{\Box}{3x - 1} + \Box$ (Simplify your answers. Do not factor.)

          Divide using long division. State the quotient, q(x), and the remainder, r(x).
$(15x^2 + 4x - 1) \div (3x - 1)$
$(15x^2 + 4x - 1) \div (3x - 1) = \frac{\Box}{3x - 1} + \Box$
(Simplify your answers. Do not factor.)

Divide using long division. State the quotient, q(x), and the remainder, r(x).
(15x^2 + 4x - 1) ÷ (3x - 1)
(15x^2 + 4x - 1) ÷ (3x - 1) = ()/(3x - 1) +
(Simplify your answers. Do not factor.)

Added by Matthew Y.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert James Kiss

08/23/2021

Step 1

15x^2 / 3x = 5x Show more…

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Divide using long division. State the quotient, q(x), and the remainder, r(x). (15x^(2)+4x-1)-:(3x-1) (15x^(2)+4x-1)-:(3x-1)=◻+(◻)/(3x-1) (Simplify your answers. Do not factor.) (Simplify your answers.Do not factor.) 15+4x-1=3-1 Divide using long division. State the quotient,qx,and the remainder,rx