Dividend per Share 2.41 1.96 1.66 0.70 3.36 3.03 2.74...

Dividend per Share 2.41 1.96 1.66 0.70 3.36 3.03 2.74 2.63 2.42 0.54 3.36 3.59 0.37 1.09 7.15 5.98 8.32 4.06 4.55 0.76 2.03 5.70 3.69 7.99 12.48 1.96 3.05 4.21 5.23 6.12 4.79 4.05 4.94 4.43 3.93 3.48 3.20 2.89 3.44 3.11 2.74 2.62 7.13 5.91 2.69 2.61 4.40 3.78 5.07 4.55 3.94 3.62 3.26 2.99 5.49 4.81 7.4 6.47 1.90 2.69 0.75 0.32 11.88 6.27 a. Calculate and interpret the measure of Skewness for the performance of the dividend per share on the Lusaka Stock Exchange. b. Calculate and interpret measure of Kurtosis of the Dividend per share of the stock c. Calculate the interquartile range and briefly explain its statistical importance d. Elaborate any two plausible data unethical practices that statistician are bound to practice on data presented on the Lusaka Stock exchange.

Transcript

00:01 Hi, i'm david and here to help you and see the question.

00:03 Now let me bring up your question here.

00:06 In the question here we're given the list in the data and then we need to build up the frequency table.

00:11 Now let me formally the table here and the first column will be the glass.

00:20 And the class here we will have the frequent that will be 205 to the smaller than 3.

00:28 So 2 .5 up to the smaller than 3 .0.

00:35 Then we'll be 3 .0 up to smaller than the 3 .5.

00:40 3 .5 up to smaller than the 4 .0.

00:45 Then 4 .0 up to smaller than the 4 .5.

00:50 4 .5 up to smaller than the 5 .0.

00:55 And then 5 .0 up to the 5 .5 and the 5 .5 up to the smaller than the 6 .0.

01:08 And the next column will be the frequency.

01:12 Now we need to count how many data will be between 2 .5 to the 3 smaller than 3.

01:18 So we have 1, 2, 3, 3, 4, 5.

01:36 5 of them then between the 3 to the 3 .5 1, 2, 3, 4, 5 of them, then between 3 .5 to the 4.

02:03 So we have 1, 2, 3, 4, oh sorry, this one will be the 1 for, this one becomes a 6 here, and miss the 3 .14 there.

02:29 So that will be only the 2 only one here and then 2 so let me remove this one so from 3 .5 to the 4 we will have 1, 2, 3, 4, 5, 5, 6, 7, 8, 9, 10, 11 and then the next one from 4 to the 4 .5.

03:12 So we have have one two three four five six seven eight eight of them from four point five five we will have one two three three four five six so we have six of them from five to five not count so one two two two we have two of them so but the 4 .9 will be here so this one will be the 7 this will be one only and then the last one we the 4 515 to the 6 the 1 2 3 4 5 5 5 6 7 7 8 9 10 of them so that would be the total i have to make sure that when i add up everything i must get the 48 so we have the 5 plus 6 plus 11 plus 8 plus 7 plus 1 plus 10 equal to the 48 and now the next column i need to find it will be i have to find the frequency already and then here the next one we have to find one is a frequency under from 3 to the 3 .5 3 to the 2 .5 so for the question being the frequency of the 3 .0 2 smaller than the 3 .5 it will equal to the 6...

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