Question

For a rectangular waveguide, prove that \frac{1}{\lambda_o^2} = \frac{1}{\lambda^2} + \frac{1}{\lambda_c^2} where $\lambda_o$ is the intrinsic wavelength at the operating frequency (i.e., $\frac{u_p}{f}$), $\lambda$ is the wavelength inside the waveguide, and $\lambda_c$ is the wavelength inside the waveguide at the cutoff frequency

          For a rectangular waveguide, prove that
\frac{1}{\lambda_o^2} = \frac{1}{\lambda^2} + \frac{1}{\lambda_c^2}
where $\lambda_o$ is the intrinsic wavelength at the operating frequency (i.e., $\frac{u_p}{f}$), $\lambda$ is the
wavelength inside the waveguide, and $\lambda_c$ is the wavelength inside the waveguide at the
cutoff frequency

For a rectangular waveguide, prove that
(1)/(^2) = (1)/(λ^2) + (1)/(^2)
where is the intrinsic wavelength at the operating frequency (i.e., (up)/(f)), λ is the
wavelength inside the waveguide, and is the wavelength inside the waveguide at the
cutoff frequency

Added by Julia F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

09/13/2023

Step 1

Step 1: Start with the equation for the intrinsic wavelength inside the waveguide at the operating frequency (P): λ = λg / √(1 - (λg / λc)^2) where λg is the wavelength inside the waveguide and λc is the wavelength inside the waveguide at the cutoff frequency. Show more…

Show all steps

Thanks for your feedback!

do not copy other answers. For a rectangular waveguide,prove that 111 2Y+zY=22 where , is the intrinsic wavelength at the operating frequency (i.e., "P), 1 is the wavelength inside the waveguide,and is the wavelength inside the waveguide at the cutoff frequency