00:02
In this question we have to find in both of this molecule which one molecule undergoes rapid e2 elimination.
00:17
So here this one molecule is a trans isomer of 1 chromo 4 tertiary utile cyclohexane.
00:40
And this one molecule is this one bromopore tertiary butyl cyclohexane.
00:58
Actually in this molecule the bromine is in equatorial position and tertiary butyl is also in equatorial position.
01:06
Both are in the same position that is equatorial.
01:08
So this is a trans is a trans isomer of one bromo or tertiary butyl.
01:15
And in this compound here we can see bromine and tertiarybutal is in equatorial and ex sorry axial position and equatorial position respectively so this is called cis isomer of one bromo for tertiary butyl cyclohexane now we can say for e2 elimination for e2 elimination base is used called ethoxide base which absorb the beta hydrogen and leaving group that is bromine is removed and for this it is compulsory that these both group means beta hydrogen and leaving group must be anti -parriplanar or we can say in transposition.
02:44
So to understood this, we can calculate or we will redraw this position again.
02:55
Now if we see the trans isomer, here this is alpha carbon and this one is beta carbon...