00:01
Let's discuss this question.
00:03
So here we have 1, 2, 3, 4, 5, 6 reactions given to us and we need to find whether this equilibrium lies to the left or the right of each acid basis.
00:14
So let's start.
00:17
Here we can say if the equilibrium lies to the left, then we can say that equilibrium constant is less than 1.
00:39
And if the equilibrium lies to right, then equilibrium constant is less than 1.
00:59
So here we can say lies to the left, so the value will be kc less than 1.
01:08
And if it is to the right, then the value of kc will be equal to greater than 1.
01:15
So now here we can say the reaction will be here we have h2 co3 plus nh3 at equilibrium gives us hco3 minus plus nh4.
01:35
So here we can say this is acid, this is base, this is conjugate base and here we have conjugate acid.
01:50
So here we can say the equilibrium lies to write as the value of kc that is equilibrium constant is greater than one.
02:10
So here we can say the stronger energy is a proton more readily than weaker one.
02:44
So here we can say equilibrium constant lies to the right that will be equilibrium constant greater than one.
02:51
And the stronger energies of proton is readily than the weaker one.
02:58
So here we can also say that the proton moves from stronger acid and became bonds bonded to stronger...