00:01
Hi, in this question we have two teenagers and they're pulling on ropes attached to a tree and the angle between the ropes, that is theta, is given as 30 degree.
00:12
So david pulls with a force f1 given as 400 newton and stephanie pulls with a force f2 given as 300 newton.
00:23
So in part a of this question we have to find the component form of the net force.
00:30
So in the vector form, the two forces acting on the tree are f1, that will be equals to minus 400 into sign of 15 icap plus cost of 15 jcap.
00:50
So on placing the values, we get the value of f1 as minus 10 .103 .5 .5.
01:02
276 i cap minus 386 .37 jcap and here the angle that each rope makes with the vertical is 15 degree.
01:18
Now f2 will be equals to 300 into sine 15 i cap minus cos 15 j cap so this will be equals to 70 0 .6457 i cap minus 289 .77 j gap.
01:42
So total force that is f vector will be equals to f1 plus f2.
01:53
So we can write f vector equals to minus 103 .5276 i cap minus 386 .5 .76 i cap minus 386...