00:03
Hi there.
00:03
In this question, we need to draw a little structure for sf2 that obeys the octet rule.
00:10
So that means we need eight electrons around each element in this structure.
00:18
Let's start out by determining how many valence electrons we have to work with.
00:21
Sulfur is in group six of the periodic table, group 6a.
00:25
So that means it has six valence electrons.
00:28
Each fluorine is in group 7a, so each fluorine has seven valence.
00:33
Electrons.
00:35
This gives us a total of 20 valence electrons and when we're drawing a loose structure, valence electrons are represented by dots.
00:47
So that means 20 dots.
00:51
All right, our single element is placed in the center.
00:54
That's the sulfur and we'll put the two fluorines on either side.
01:00
We know that we have to have at least a single bond holding each fluorine to the sulfur.
01:08
So we'll put in our bonds.
01:10
That uses up four of our electrons.
01:11
We have 16 remaining.
01:14
So let's go ahead and start completing octets until we run out of dots.
01:25
All right.
01:25
So far, i've used a total of 16.
01:27
So i have four more dots, which are going to fit nicely on the sulfur.
01:34
So everything has an octet.
01:35
We've used exactly 20 dots.
01:38
So this is our lewis structure.
01:40
Let's go ahead and answer our questions then for the sulfur atom.
01:44
As we look at that, we see that it has two lone pairs on the sulfur.
01:56
So two lone pairs, we see that it has two single bonds.
02:18
And there are no zero, in other words, double bonds...